How do you solve $8 = 2^{x + 4}$ $8 = 2^(x + 4)$ ?

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Answer 1 · 2016-04-09T20:42:48

$x = - 1$ $x=-1$

$8 = 2^{x + 4} = ?$ $8=2^(x+4)=?$

$2^{3} = 2^{x + 4}$ $2^3=2^(x+4)$

$hence the equation above has the same base value$ $" hence the equation above has the same base value"$

$3 = x + 4$ $3=x+4$

$x = 3 - 4$ $x=3-4$

$x = - 1$ $x=-1$

How do you solve 8 = 2^(x + 4)8=2x+48 = 2^(x + 4)?