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How do you solve $8 = {log}_{2} x$ $8=log_2 x$ ?

1 Answer

Jan 29, 2016

here is how,

Explanation:

$8 = {log}_{2} x$ $8=log_2x$

$or, 2^{8} = 2^{{log}_{2} x}$ $or,2^8=2^(log_2x)$

$or, x = 2^{8}$ $or,x=2^8$

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