How do you solve #81-1/25x^2=0#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer 256 Jan 21, 2017 #81-1/25x^2=0 => x=45# Explanation: #81-1/25x^2=0# #<=># #81=1/25x^2# add #1/25x^3# to both sides #<=># #2025=x^2# Multiply both sides by 25 #<=># #sqrt(2025)=x# take the square root of both sides #<=># #x=sqrt(25)sqrt(81)=5(9)=45# Simplify Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 2385 views around the world You can reuse this answer Creative Commons License