How do you solve #8x^2 + 28x + 12 = 0# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Konstantinos Michailidis Sep 28, 2015 See explanation Explanation: We have that #8x^2+28x+12=0=>4*(2x^2+7x+3)=0=>2x^2+7x+3=0=> 2x^2+6x+x+3=0=>2x(x+3)+(x+3)=0=>(2x+1)(x+3)=0=> x=-1/2 or x=-3# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 1667 views around the world You can reuse this answer Creative Commons License