How do you solve $8 x^{2} - 5 x - 3 = 0$ $8x^2 - 5x - 3 = 0$ by completing the square?

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Answer 1 · 2016-08-16T12:49:35

$x = 1, - \frac{3}{8}$ $x=1, -3/8$

$8 x^{2} - 5 x = 3$ $8x^2-5x=3$

$x^{2} - \frac{5}{8} x = \frac{3}{8}$ $x^2-5/8x=3/8$

$x^{2} - \frac{10}{16} x = \frac{3}{8}$ $x^2-10/16x=3/8$

$x^{2} - \frac{10}{16} x + \frac{25}{256} = \frac{3}{8} + \frac{25}{256}$ $x^2-10/16x+25/256=3/8+25/256$

${(x - \frac{5}{16})}^{2} = \frac{121}{256}$ $(x-5/16)^2=121/256$

$x - \frac{5}{16} = \pm \frac{11}{16}$ $x-5/16=+-11/16$

$x = (\pm \frac{11}{16}) + \frac{5}{16}$ $x=(+-11/16)+5/16$

$x = \frac{5 \pm 11}{16}$ $x=(5+-11)/16$

$x = 1, - \frac{3}{8}$ $x=1, -3/8$

How do you solve 8x2−5x−3=08x^2 - 5x - 3 = 0 by completing the square?