How do you solve $9^{2 y} = 66$ $9^(2y) = 66$ ?

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How do you solve $9^{2 y} = 66$ $9^(2y) = 66$ ?

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Answer 1 · 2016-03-28T17:25:35

$y = (\frac{1}{2}) (\frac{log 66}{log 9})$ $y=(1/2)(log 66/log 9)$ =0.9534, nearly.

Explanation:

Equating logarithms, $log (9^{2 y}) = log 66$ $log(9^(2y))=log 66$ .
So, 2y log 66 = log 9, using $log (a^{m}) = m log a$ $log(a^m)=mlog a$ ..
$y = (\frac{1}{2}) (\frac{log 66}{log 9})$ $y=(1/2)(log 66/log 9)$

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How do you solve $9^{2 y} = 66$ $9^(2y) = 66$ ?

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