Question

How do you solve `9^(8x)=13^(-x+7)`?

Answer 1

`x=7-8log(9)/log(13)`

Explanation:

`9^(8x)=13^(-x+7)`

You need to use logarithms:

`8x. log(9)=(-x+7)log(13)`

`8log(9)/log(13)=-x+7`

`x=7-8log(9)/log(13)`

It is a very ugly solution.