How do you solve #|a+1|\le 4#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer KillerBunny Jun 8, 2018 #-5\le a\le 3# Explanation: By definition, #|x|\le k \iff -k \le x \le k# So, #|a+1|\le 4 \iff -4 \le a+1 \le 4# Subtract #1# from all sides to get #-5\le a\le 3# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? How do you solve #abs(x - 7)<10#? See all questions in Absolute Value Inequalities Impact of this question 6855 views around the world You can reuse this answer Creative Commons License