How do you solve by completing the square $9x^2+6x=8$ ?

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Answer 1 · 2015-04-01T13:18:21

I would try:
$x^2+6/9x=8/9$
$x^2+2/3x=8/9$
$x^2+2/3x+1/9-1/9=8/9$
$(x+1/3)^2=8/9+1/9$
$x+1/3=+-sqrt(1)$
$x=-1/3+-1$
$x_1=2/3$
$x_2=-4/3$

How do you solve by completing the square 9x^2+6x=89x^2+6x=8?