How do you solve by completing the square x^2 - 4x - 1 = 0x2−4x−1=0?
1 Answer
Mar 30, 2015
The roots are 2+
Rewrite it as x^2 -4x +4-4-1=0
x^2 -4x+4=5
(x-2)^2 =5
x-2= +
x= 2 +
The roots are 2+
Rewrite it as x^2 -4x +4-4-1=0
x^2 -4x+4=5
(x-2)^2 =5
x-2= +
x= 2 +