How do you solve by completing the square $x^2+4x-32=0$ ?

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Answer 1 · 2015-04-01T13:09:04

I would try:
$x^2+4x=32$
$x^2+4x+4-4=32$
$x^2+4x+4=32+4$
$(x+2)^2=36$
$x+2=+-sqrt(36)$
$x=-2+-6$
$x_1=-8$
$x_2=4$

How do you solve by completing the square x^2+4x-32=0x^2+4x-32=0?