How do you solve by completing the square $x^{2} + 8 x = 9$ $x^2+8x=9$ ?

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How do you solve by completing the square $x^{2} + 8 x = 9$ $x^2+8x=9$ ?

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Answer 1 · 2015-04-03T17:28:26

$x^{2} + 8 x - 9 = 0$ $x^2+8x-9=0$
$(x^{2} + 8 x + {(\frac{8}{2})}^{2} - {(\frac{8}{2})}^{2}) - 9 = 0$ $(x^2 +8x +(8/2)^2 -(8/2)^2) - 9 = 0$
$(x^{2} + 8 x + 16 - 16) - 9 = 0$ $(x^2+8x+16-16) - 9 = 0$
$(x^{2} + 8 x + 16) - 16 - 9 = 0$ $(x^2+8x+16) - 16 - 9 = 0$
${(x + 4)}^{2} - 25 = 0$ $(x+4)^2 - 25 = 0$

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How do you solve by completing the square $x^{2} + 8 x = 9$ $x^2+8x=9$ ?

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How do you solve by completing the square $x^{2} + 8 x = 9$ $x^2+8x=9$ ?