How do you solve $e^{- 2 x + 1} = 14$ $e^(-2x+1)=14$ ?

Question

3571 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-11T04:05:16

${ln e}^{- 2 x + 1} = ln 14$ $lne^(-2x + 1) = ln14$

$(- 2 x + 1) ln e = ln 14$ $(-2x + 1)lne = ln14$

$- 2 x + 1 = ln 14$ $-2x + 1 = ln14$

$- 2 x = ln 14 - 1$ $-2x = ln14 - 1$

$x = - \frac{ln 14 - 1}{2}$ $x = -(ln14 - 1)/2$

How do you solve e−2x+1=14e^(-2x+1)=14?