How do you solve $e^(4x - 6) - 8 = 11212$ ?

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Answer 1 · 2016-02-07T20:25:36

$x=ln(root(4)(11220e^6))$

$e^(4x-6)-8=11212$

$e^(4x-6)=11220$

$4x-6=ln(11220)$

$4x=ln(11220)+6$

$x=(ln(11220)+6)/4$

How do you solve e^(4x - 6) - 8 = 11212e^(4x - 6) - 8 = 11212?