How do you solve $e^{5 - 9 x} = 990$ $e^(5-9 x)=990$ ?

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Answer 1 · 2016-03-31T14:16:35

$x = \frac{5 - ln 990}{9}$ $x=(5-ln 990)/9$ .

If $e^{m} = n$ $e^m=n$ , inversely, m = ln n

Here, $e^{5 - 9 x} = 990$ $e^(5-9x)=990$ . $m = 5 - 9 x, n = 990$ $m=5-9x, n=990$ .

Inversely, $5 - 9 x = ln 990$ $5-9x=ln 990$ .

$9 x = 5 - ln 990$ $9x = 5-ln 990$ .

$x = \frac{5 - ln 990}{9}$ $x=(5-ln 990)/9$ .

How do you solve e5−9x=990e^(5-9 x)=990?