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How do you solve $e^{5 x + 1} = 40$ $e^(5x + 1) = 40$ ?

1 Answer

Oct 23, 2015

$x ≅ 0.53778$ $x ~= 0.53778$

Explanation:

Given
$XXX e^{5 x + 1} = 40$ $color(white)("XXX")e^(5x+1) = 40$

Therefore
$XXX 5 x + 1 = ln (40)$ $color(white)("XXX")5x+1 = ln(40)$

Using a calculator: $ln (40) ≅ 3.6889$ $ln(40) ~= 3.6889$

$XXX 5 x + 1 ≅ 3.6889$ $color(white)("XXX")5x+1 ~= 3.6889$

$XXX x ≅ 0.53778$ $color(white)("XXX")x ~= 0.53778$

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