How do you solve $e^{x + 6} = 4$ $e^(x+6) = 4$ ?

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Answer 1 · 2015-07-17T17:27:37

Take the natural logarithm of both sides, then subtract $6$ $6$ from both sides to find:

$x = {log}_{e} (4) - 6 ≅ - 4.6137$ $x = log_e(4)-6 ~= -4.6137$

Taking ${log}_{e}$ $log_e$ of both sides we get:

${log}_{e} (4) = {log}_{e} (e^{x + 6}) = x + 6$ $log_e(4) = log_e(e^(x+6)) = x + 6$

Subtract $6$ $6$ from both ends to get:

$x = {log}_{e} (4) - 6 ≅ 1.3863 - 6 = - 4.6137$ $x = log_e(4) - 6 ~= 1.3863 - 6 = -4.6137$

How do you solve ex+6=4e^(x+6) = 4?