Question

How do you solve for t `A= Ba^(ct)+D`?

Answer 1

`t=(A-D)/(Bclna)`

Explanation:

`A=Ba^(ct)+D`

`Ba^(ct)=A-D`

`a^(ct)=(A-D)/B`

`ctlna=(A-D)/B`

`t=(A-D)/(Bclna)`