How do you solve for the voltages and currents in this circuit diagram?

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How do you solve for the voltages and currents in this circuit diagram?

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Answer 1 · 2016-06-26T06:50:33

Please see below.

Explanation:

As $R_{1}$ $R_1$ and $R_{2}$ $R_2$ are in parallel, the resultant resistance $R$ $R$ will be given by $\frac{1}{R_{1}} + \frac{1}{R_{2}}$ $1/(R_1)+1/(R_2)$ .

Hence $\frac{1}{R} = \frac{1}{3} + \frac{1}{6} = \frac{1}{2}$ $1/R=1/3+1/6=1/2$ and hence $R = 2$ $R=2$ $Omega$ .

As the voltage of battery source is $120V$ , assuming $0$ internal resistance, current passing through circuit or $R_3$ is $I_0=120/(15+2)=120/17=7 1/17$ ampere.

and hence voltage $V_3$ across it will be $120/17xx15=1800/17= 105 15/17V$

and that across other two resistances i.e. $V_1=V_2$ will be $120-1800/17=240/17V$ each.

Hence current $I-1$ passing through $R_1$ is $240/17xx1/3=80/17=4 12/17$ ampere.

and current passing $I_2$ through $R_2$ is $240/17xx1/2=120/17=7 1/17$ ampere.

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How do you solve for the voltages and currents in this circuit diagram?

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