How do you solve for x in #1000 = 20e^(x/4)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Apr 9, 2016 #x=15.648# Explanation: #1000=20*e^(x/4)# or #e^(x/4)=1000/20=50# Taking log with base #e# of both sides gives us, #x/4=ln50=3.912# and #x=3.912xx4=15.648# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1949 views around the world You can reuse this answer Creative Commons License