How do you solve for x in $9 = 2^{.84 x}$ $9=2^(.84x)$ ?

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Answer 1 · 2015-12-05T15:38:25

$x \approx 3.77$ $x~~3.77$ to 2 decimal places

Suppose we had $log (x^{3})$ $log(x^3)$

This is $log (x \times x \times x)$ $log(x xx x xx x )$

Which is $log (x) + log (x) + log (x)$ $log(x)+log(x)+log(x)$

Which is $3 log (x)$ $3log(x)$
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Given: $9 = 2^{0.84 x}$ $9=2^(0.84x)$

Take logs of both sides

$log (9) = 0.84 x log (2)$ $log(9) = 0.84xlog(2)$

$x = \frac{log (9)}{0.84 \times log (2)}$ $x=(log(9))/(0.84xxlog(2))$

$x \approx 3.77$ $x~~3.77$ to 2 decimal places

How do you solve for x in 9=2.84x9=2^(.84x)?