How do you solve for x in 90e−.879x=225? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan May 19, 2016 x=ln0.40.879=−1.042424, nearly. Explanation: Here, e0.879=90225=0.4 Inversely, 0.879 x= ln 0.4 So, x=ln0.40.879=−1.042424, nearly Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9x−4=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2log4(x+7)−log4(16)=2? How do you solve 2logx4=16? How do you solve 2+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 1363 views around the world You can reuse this answer Creative Commons License