How do you solve for x in $log (4 x - 1) = 5$ $log(4x-1)=5$ ?

Question

How do you solve for x in $log (4 x - 1) = 5$ $log(4x-1)=5$ ?

1 Answer

Impact of this question

1394 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-26T20:14:27

$x = \frac{100001}{4}$ $x=100001/4$

Explanation:

Assuming the base of the logarithm is 10 then

$log (4 x - 1) = 5 \Rightarrow 4 x - 1 = 10^{5} \Rightarrow x = \frac{1}{4} \cdot (1 + 10^{5}) = \frac{100001}{4}$ $log(4x-1)=5=>4x-1=10^5=>x=1/4*(1+10^5)=100001/4$

Science

Math

Humanities

... and beyond

How do you solve for x in $log (4 x - 1) = 5$ $log(4x-1)=5$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve for x in log(4x−1)=5log(4x-1)=5?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve for x in $log (4 x - 1) = 5$ $log(4x-1)=5$ ?