How do you solve for x in #log10^(x^2)=4#?
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"How do I change #int_0^1int_0^sqrt(1-x^2)int_sqrt(x^2+y^2)^sqrt(2-x^2-y^2)xydzdydx# to cylindrical or spherical coordinates?"
1 Answer
Jan 13, 2016
Explanation:
As Real valued functions,
So:
#4 = log(10^(x^2)) = x^2#
Hence
