How do you solve for x in $y=(e^x-e^-x)/6$ ?

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Answer 1 · 2016-12-21T19:51:34

$x = sinh^-1(3y)$

$3y = (e^x - e^-x)/2$

It has been found that $sinhx = (e^x- e^-x)/2$ , where $y = sinhx$ is the hyperbolic sine function.

Thus,

$3y = sinhx$

$sinh^-1(3y) = x$

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How do you solve for x in y=(e^x-e^-x)/6 y=(e^x-e^-x)/6 ?