How do you solve \frac { 1} { 5} = 5^ { x - 1}? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer LM Dec 18, 2016 x = 0 Explanation: 1/a^m = a^-m 1/5 = 1/5^1 =5^-1 substitute power for x - 1: x - 1 = -1 add 1: x = 0 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 956 views around the world You can reuse this answer Creative Commons License