How do you solve #\frac { 1} { 9} = 9^ { 4x }#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Monzur R. Apr 6, 2018 #x=-1/4# Explanation: #1/9=9^(4x)# But #1/9=9^-1# So #9^-1=9^(4x)rArr-1=4xrArrx=-1/4# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1065 views around the world You can reuse this answer Creative Commons License