Question

How do you solve `ln e^(-2x) = 8`?

Answer 1

I found: `x=-4`

Explanation:

We can first take the `-2x` and place it in front of the log:

`-2xlne=8`

then remember that: `lne=1`
and write:

`-2x=8`
so that `x=-8/2=-4`