How do you solve #ln(2x+3)-4=15#?

1 Answer
Sep 27, 2015

#x = (e^19 - 3)/2#

Explanation:

#ln(2x+3) - 4 = 15#
#ln(2x+3) = 19#

Take the exponential of both sides, then solve using algebra

#2x + 3 = e^19#
#2x = e^19 - 3#
#x = (e^19 - 3)/2#

Double checking this value gives the right answer, and when x is that value we aren't taking the logarithm of a negative or a null number so all's okay.