How do you solve $ln (2x-5) = 3.78$ ?

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Answer 1 · 2016-01-18T08:47:59

I found: $x=(e^(3.78)+5)/2=24.41$

I would use the definition of log to change it into an exponential as:
$2x-5=e^(3.78)$
Rearranging:
$2x=e^(3.78)+5$
And:
$x=(e^(3.78)+5)/2=24.41$

How do you solve ln (2x-5) = 3.78ln (2x-5) = 3.78?