How do you solve $ln (4 + x) = 2$ $ln(4 + x) = 2$ ?

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Answer 1 · 2016-05-18T03:13:38

You must understand that the opposite operation of a ln (natural logarithm) is $e$ $e$ , the natural exponent.

$4 + x = e^{2}$ $4 + x = e^2$

$x = e^{2} - 4 or 3.39$ $x = e^2 - 4 or 3.39$

How do you solve ln(4+x)=2ln(4 + x) = 2 ?