How do you solve #ln(6x-5)=3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Sep 6, 2016 #x=4.1809# Explanation: As #ln(6x-5)=3# #6x-5=e^3# or #6x=e^3+5# i.e #x=(e^3+5)/6=(20.0855+5)/6=25.0855/6=4.1809# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 9194 views around the world You can reuse this answer Creative Commons License