How do you solve $ln sqrt(x+1)=2$ ?

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Answer 1 · 2015-12-17T20:58:46

$x=e^4-1$

$lnsqrt(x+1)=2$

$thereforeln(x+1)^(1/2)=2$

$therefore 1/2ln(x+1)=2$

$thereforeln(x+1)=4$

$therefore(x+1)=e^4$

$thereforex=e^4-1$

How do you solve ln sqrt(x+1)=2ln sqrt(x+1)=2?