How do you solve $ln (x + 1) - ln x = 2$ $Ln(x+1)-lnx=2$ ?

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Answer 1 · 2018-04-27T23:46:29

$x = 0.157$ $x=0.157$

$I n (x + 1) - I n (x) = 2$ $In(x+1)-In(x)=2$

$I n (\frac{x + 1}{x}) = 2$ $In((x+1)/x)=2$

$\frac{x + 1}{x} = e^{2}$ $(x+1)/x=e^2$

$x + 1 = x e^{2}$ $x+1=xe^2$

$x (1 - e^{2}) = - 1$ $x(1-e^2)=-1$

$x = \frac{1}{e^{2} - 1}$ $x=1/(e^2-1)$

$x = 0.157$ $x=0.157$

How do you solve ln(x+1)−lnx=2Ln(x+1)-lnx=2?