Question

How do you solve `Ln x^2=4`?

Answer 1

I found: `x=e^2=7.389`

Explanation:

You can use a property of the logs and write:
`lnx^2=2lnx`
so that you have:
`2lnx=4`
`lnx=4/2=2`
so that `x=e^2`