Question

How do you solve `ln(x+2)+ln(x-2)=3`?

Answer 1

You can write it as:
`ln[(x+2)×(x-2)]=3`
And:
`(x+2)×(x-2)=e^3=20`
So you have:
`x^2-4=20`
`x^2=24`
`x=+-sqrt(24)`
`x=+-2sqrt(6)`
We use the positive answer in our original expression.