How do you solve $ln(x+4)=ln7$ ?

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Answer 1 · 2016-07-16T21:37:19

Taking the $e$ -xponential of both sides we get

$cancel(e)^(cancel(ln)(x+4)) = cancel(e)^(cancel(ln) 7)$

$x+4 = 7$

Subtracting $4$ from both sides gives us our final answer of

$x = 3$

How do you solve ln(x+4)=ln7ln(x+4)=ln7?