Question

How do you solve `ln y = 2x + 4`?

Answer 1

`y=e^(2x+4)`

Explanation:

Assuming the goal is to isolate `y`, we can do so by raising both sides as a power of `e`, cancelling the natural logarithm:

`e^ln(y)=e^(2x+4)`

`y=e^(2x+4)`