How do you solve #ln4-lnx=10#?

1 Answer
Alan P.
Nov 29, 2015

#x=4/(e^10)=~~1.82xx10^(-4)#

Explanation:

#ln(4) - ln(x) =10#

#color(white)("XXXXXXXXXX")#since #log(a/b) = log(a)-log(b)#
#rArr ln(4/x) = 10#

#color(white)("XXXXXXXXXX")#taking each side of the above as an exponent of #e#
#rArr 4/x = e^10#

#color(white)("XXXXXXXXXX")#algebraic simplification
#rArr x = 4/(e^10)#

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