How do you solve $ln x = - 1$ $lnx=-1$ ?

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Answer 1 · 2017-01-26T08:04:04

$\frac{1}{e}$ $1/e$

$ln x = - 1 \Rightarrow {log}_{e} x = - 1$ $lnx=-1=>log_(e)x=-1$

$\Rightarrow e^{- 1} = x$ $=>e^(-1)=x$

$:.x=1/e$

How do you solve lnx=-1lnx=−1lnx=-1?