How do you solve (lnx)^2 -1 = 0?

1 Answer
Dec 22, 2015

Rearrange then take exponents to find:

x = e or x = 1/e

Explanation:

Add 1 to both sides of the equation to get:

(ln x)^2 = 1

Hence:

ln x = +-1

By definition of ln we know e^(ln x) = x. Hence:

x = e^(ln x) = e^(+-1)

That is x = e or x = 1/e