How do you solve (lnx)^2 -1 = 0?
1 Answer
Dec 22, 2015
Rearrange then take exponents to find:
x = e orx = 1/e
Explanation:
Add
(ln x)^2 = 1
Hence:
ln x = +-1
By definition of
x = e^(ln x) = e^(+-1)
That is