How do you solve $lnx-ln(x+2)=1$ ?

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Answer 1 · 2015-12-08T12:41:54

There is no Real solution to this equation

$ln(x) < ln(x+2)$

$rArr ln(x)-ln(x+2) < 0$

$.: ln(x)-ln(x+2) != +1$ for any value of $x$

How do you solve lnx-ln(x+2)=1lnx-ln(x+2)=1?