How do you solve $ln x + ln (x - 2) = ln 3$ $lnx + ln(x-2) = ln3$ ?

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Answer 1 · 2016-04-21T18:55:05

$x \approx 2.45$ $x~~2.45$

$ln (x (x - 2)) = ln 3$ $ln(x(x-2))=ln3$

$ln (x^{2} - 2 x) = ln 3$ $ln(x^2-2x)=ln3$

$x^{2} - 2 x - ln 3 = 0$ $x^2-2x-ln3=0$

$x = \frac{2 \pm \sqrt{4 + 4 ln 3}}{2}$ $x=(2+-sqrt(4+4ln3))/2$

$x \approx 2.45 or x \approx - 0.45$ $x~~2.45 or x~~-0.45$

$x \approx 2.45$ $x~~2.45$

How do you solve lnx + ln(x-2) = ln3lnx+ln(x−2)=ln3lnx + ln(x-2) = ln3?