How do you solve #log(1/x)=7.761#?

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Answer 1 · 2016-01-02T10:11:09

By simply solving with the exponential form.

#x=0.12885#

#log(1/x)=7.761#

Supposing that the base is 10:

#log(1/x)=log10^7.761#

Since #log# is a 1-1 function for #x>0# and #x!=1# the #log# can be cancelled out:

#1/x=10^7.761#

#x=1/10^7.761=10^-7.761=0.12885#