Question

How do you solve `log_10 3z=2`?

Answer 1

`z = 33 1/3`

Explanation:

`log_"10" 3z = 2`

Understand this for easy to remember,
`if 100 =10^2`, then
`log_"10"100=2`

`3z = 10^2`

`3z = 100`

`z = 100/3`
`z = 33 1/3`