How do you solve $log_10 3z=2$ ?

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Answer 1 · 2017-01-12T02:34:06

$z = 33 1/3$

$log_"10" 3z = 2$

Understand this for easy to remember,
$if 100 =10^2$ , then
$log_"10"100=2$

$3z = 10^2$

$3z = 100$

$z = 100/3$
$z = 33 1/3$

How do you solve log_10 3z=2log_10 3z=2?