How do you solve ${log}_{10} x = - 1$ $log_10 x=-1$ ?

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Answer 1 · 2016-02-27T13:23:26

Take $10$ $10$ to the power of each side of the equation to find that

$x = \frac{1}{10}$ $x=1/10$

By their definition, logarithms have the property that $a^{{log}_{a} (x)} = x$ $a^(log_a(x))=x$

Using that, we have

${log}_{10} (x) = - 1$ $log_10(x) = -1$

$\Rightarrow 10^{{log}_{10} (x)} = 10^{- 1}$ $=>10^(log_10(x)) = 10^(-1)$

$\Rightarrow x = 10^{- 1} = \frac{1}{10}$ $=>x=10^(-1)=1/10$

How do you solve log10x=−1log_10 x=-1?