How do you solve $log_10x=-1$ ?

Question

4717 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-30T08:27:19

$x = frac(1)(10)$

We have: $log_(10)(x) = - 1$

A logarithmic number can be expressed in the following way:

$" " " " " " " " " " " " " " log_(a)(b) = y <=> a^(y) = b$

Using this method, we can isolate $x$ , and hence solve the equation.

So let's do it:

$Rightarrow log_(10)(x) = - 1 <=> 10^(- 1) = x$

$Rightarrow log_(10)(x) = - 1 <=> frac(1)(10) = x$

$Rightarrow x = frac(1)(10)$

Therefore, the solution of the equation is $x = frac(1)(10)$ .

How do you solve log_10x=-1log_10x=-1?