How do you solve log _16(x - 4) = log _3(3 - x)log16(x−4)=log3(3−x)?

1 Answer
Johnson Z.
Mar 28, 2016

x="no solution"x=no solution

Explanation:

There is no solution to this logarithmic equation. If you try to substitute x=2,3,4, "or"x=2,3,4,or 55 into the equation, you will always end up taking the logarithm of a negative number, which is not possible.

log_16(x-4)=log_3(3-x)log16(x−4)=log3(3−x)

color(green)(|bar(ul(color(white)(a/a)x="no solution"color(white)(a/a)|)))

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