Question

How do you solve `log _16(x - 4) = log _3(3 - x)`?

Answer 1

`x="no solution"`

Explanation:

There is no solution to this logarithmic equation. If you try to substitute `x=2,3,4, "or"` `5` into the equation, you will always end up taking the logarithm of a negative number, which is not possible.

`log_16(x-4)=log_3(3-x)`

`color(green)(|bar(ul(color(white)(a/a)x="no solution"color(white)(a/a)|)))`