How do you solve $log_2 (3x)>log_2 5$ ?

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Answer 1 · 2017-02-09T02:03:19

See below :)

If the Socratic graphing utility wasn't so useless, one might be able to graph the log function here and show the whole picture.

But IF we assume that $log_(n) A > log_(n) B implies A > B$ then we can say that, with your problem, $3x > 5 implies x > 5/3$

Desmos draws it thusly!

How do you solve log_2 (3x)>log_2 5log_2 (3x)>log_2 5?