How do you solve $log_2(log_4x) = 1$ ?

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Answer 1 · 2015-12-04T16:12:37

Use exponentiation ...

$2^(log_2(log_4x))=2^1=2$

$4^(log_4x)=4^2=16$

$x=16$

hope that helped

How do you solve log_2(log_4x) = 1log_2(log_4x) = 1?